All mathematicians of the world, you all must read this article.

Toy Soldiers

Han Erim

25 August 2008

Copyright 2008 © Han Erim All Rights Reserved.

You will see here how, by putting aside the rules of mathematics, physicists have suffered a terrible brain trauma. When you realize that even those physicists with whom you share the same corridors, whom you respect, and even call your friends, have also caught this disease, you will be even more surprised.

Let us pose the problem:

There are three elements, called A, B and C. These three elements are at the same time common sub-elements of two larger systems which we call the “First System” and the “Second System”. For the First System, the following relation holds between the three elements: A = B = C. For the Second System we have B = C. Since, for the First System, A = B = C, does the equality A = B = C also hold for the Second System, or not? (Figure 1)

Since A–B–C are common elements for both systems, there is only one possible answer to this question. They must be equal; they are equal. When we carry out a mathematical proof, we make use of the existing equalities and deduce what the unknown is equal to. There is no other way.

But unfortunately, for today’s physicists, no such rule exists. Because the answer physicists give to the question above is: for the First System A = B = C, and for the Second System B = C but A ≠ B and A ≠ C. I am not joking. I am talking about a very serious and important issue.

Now let us see what is happening more clearly. At our starting point we have three rulers and three clocks that are equal to each other. We call them A, B and C. (Figure 2)

We place two of the clocks and rulers on two small wagons and pull them towards the symmetry axis with equal speed. When we ask physicists whether the clocks and rulers are equal to each other, according to the Symmetry Axis (1st Reference System), they easily answer: THEY ARE EQUAL. A = B. (Here, by equal we mean that both clocks tick at the same rate and the ruler lengths remain the same relative to each other.) (Figure 3)

This time we place the two small wagons on a train moving at constant speed and again pull them towards the symmetry axis with equal speed. When we ask physicists whether the clocks and rulers are equal to each other according to the Symmetry Axis (1st Reference System), physicists again easily answer: THEY ARE EQUAL. A = B.

Let us add a short note here as an explanation: To claim that the clocks on the wagons on the train do not run equally according to the symmetry axis means that, while inside a system in uniform rectilinear motion, one could determine one’s own speed and direction solely based on one’s own reference frame. Such an assumption contradicts all known principles of physics. Neither in Newtonian physics, nor in Einstein’s physics, nor in Alice physics is there such a concept, nor can there be. (Figure 4)

In the third stage we place the third ruler and clock on the ground. And we say: let the speed of the train to the right and the speed with which the right-hand wagon is pulled towards the symmetry axis be equal. In this case, according to the First System, C on the ground and B on the wagon will approach the symmetry axis with equal speed. Therefore, for the First System the equality B = C holds, and as a result, for the First System A = B = C. (Figure 5)

According to the ground (Second Reference System), B on the wagon is at rest. Therefore, for the Second System the equality B = C holds. We had already shown, based on the 1st System, that A = B. Therefore, for the Second System as well, the equality A = B = C holds.

Now I will show you, in a much clearer way, that A = B according to the ground in all cases. Let us imagine a long slider whose midpoint can always move up and down along the symmetry axis. Let us connect both ends of the slider to the minute hands of the clocks, which we call A and B. The points where the minute hands are attached to the slider are free to move inside the slider. We assume that this arrangement has no effect on the running rates of the clocks. In this way we obtain a simple mechanical device. The inclination of the slider will be determined by the rotational motion of the minute hands. If both clocks run at the same rate, the inclination of the slider will remain constant; if they run differently, the inclination of the slider will change. (Figure 6)

Let us assume that the clock called A is moving and approaches B with a constant speed. While A moves towards B, a pen placed on the left side of the slider draws the position of the point on which it is located. In this way we obtain a trajectory showing the motion of the slider. Now let us see what happens: When both clocks run at the same rate, the trajectory drawn by the pen will be a regular sine curve (Figure 7). If the clocks do not run equally with respect to each other, the trajectory drawn by the pen will deviate from this ideal sine curve (Figure 8).

Now we can carry out our proof: It is clear that, whatever the speeds and directions of the two clocks may be, it is always possible to choose a symmetry axis with respect to these clocks. The position of the symmetry axis is the midpoint of the distance between the two clocks, and its speed is half the sum of the speeds of the two clocks. For a reference system located on the symmetry axis, we already know that both clocks run equally (Figure 4). Therefore, for the reference system belonging to the symmetry axis, the pen must necessarily draw a regular sine-curve trajectory.

Returning to our example: if, for the ground reference system, a difference in the running rates of A and B were to occur, then for the ground reference system the pen would have to draw a second, irregular trajectory as well. However, it is obvious that this is impossible: the pen can only draw a single trajectory; it cannot draw two different trajectories at the same time. The trajectory drawn by the pen will always be the trajectory belonging to the symmetry axis and will show that both clocks run equally. This trajectory is valid for all reference systems and shows that both clocks run equally. The trajectory that is drawn is independent of the speeds of the clocks, of where the reference system is located, or of the speeds of the reference systems. Therefore, for all reference systems and under all conditions, A = B. Both clocks run equally. (Figure 9)

The proof given here also declares that the Special Theory proposed by Albert Einstein has reached its end. In fact, his theory had already ended seven years ago, when Alice Law was published. In Alice Law, what Special Relativity is and how it occurs are explained in great detail, with decisive proofs like the one here. I recommend that everyone who wonders what Relativity really is should read Alice Law.

However, for seven years there has been something that is not going well. Physicists, in great comfort, behave as if Alice Law had never been written, as if the proofs given here had never been made. Do not think that they have not read Alice Law; many physicists have read it. A physicist who is in his right mind and honest with himself should put his pen down after reading the proof on this page. But they do not...

The price of the disease that physicists have caught is not paid only by them. Whichever branch of science you look at, you will see that they depend on the information provided by physicists. Astronomers, space studies and others—how can they reach correct results in their work if they build on wrong information? By taking on this task, you will not only help physicists, but also the entire scientific community, and at the same time, yourself.

As for whether I am showing you the truth here, you should not look at words but at mathematics. I say that A = B = C. From time to time I wonder whether I will ever meet a physicist who, when confronted with the truth, turns toward the truth. Until today this has not happened. Who knows, maybe one day I will be fortunate.

Han Erim